Question

In solvents like $DMSO$, acetonitrile, $F^{-}$ ion of dissolved $NaF$ is more reactive than in methyl alcohol. Explain.

• A. ${CH}_{3}OH$ is more polar than $DMSO$ and ${CH}_{3}CN$..
• B. ${CH}_{3}OH$ is less polar than $DMSO$ and ${CH}_{3}CN$.
• C. unsolvated $F^{-}$ ion is $DMSO$ or ${CH}_{3}CN$ acts more effectively as nuleophile.
• D. $-OH$ group is better leaving group than $F^{-}$ ion.

Answer 1

The correct option is C unsolvated $F^{-}$ ion is $DMSO$ or ${CH}_{3}CN$ acts more effectively as nuleophile.

In methyl alcohol $F^{-}$ is solvated but in $DMSO$ or ${CH}_{3}CN$ (aprotic solvent ) $F^{-}$ ion is not solvated. Unsolvated $F^{-}$ ion acts more effectively as a nucleophile.