Question

In $s{p}^3{d}^2$ hybridisation, which sets of $d$-orbitals is involved?

• A. $d_{x^2-y^2},d_{z^2}$
• B. $d_{z^2},d_{xy}$
• C. $d_{xy}$, $d_{yz}$
• D. $d_{x^2-y^2},d_{xy}$

Answer 1

The correct option is A $d_{x^2-y^2},d_{z^2}$

While forming the bonds, bonds should be formed parallel to the $X,Y$ and $Z$ axes, So that bonds will be more stronger. Hence, $d_{x^2-y^2}$ and $d_{z^2}$ will be used to form the hybrid orbitals.

Therefore for $d^2{sp}^3$ and ${sp}^3{d}^2,d_{x^2-y^2}$ and $d_{z^2}$ orbitals are used.