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Question

In specific gravity test the following observations were made
Weight of dry soil : 50 N
Weight of bottle + soil + water : 100 N
Weight of bottle + water : 85.5 N

If while obtaining the weight 100 N, 3 ml air remained entrapped in suspension, then the percentage error obtained in measuring the specific gravity of soil solids is

A
0.08%
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B
0.06%
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C
0.04%
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D
0.03%
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Solution

The correct option is A 0.08%
G=W2W1(W2W1)(W3W4)=5050(10085.5)

G=1.4085

If some air is entrapped while the weight W3 is taken, the observed value of W3 will be lower than if water is occupied by air space.

W3=100+0.03=100.03

Correct G=5050(100.0385.5)
G=1.4096

Percentage error =1.40961.40851.4096×100=0.08%

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