In square PQRS. if PQ $= 3 x - 7$ and $Q R = x + 3$ ; find PS.

6

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7

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8

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5

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Solution

The correct option is C $8$
In square $P Q R S P Q = Q R$ (Since all the sides of a square are equal)

$\Rightarrow 3 x - 7 = x + 3$

$\Rightarrow x = 5$

Hence putting the value of $x$ we get

PQ $= 3 (5) - 7$

Therefore, PQ $= 8$ units

Hence PS $= 8$ units (Since all the sides of a square are equal)

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In square PQRS if $P Q = (3 x - 7)$ units and $Q R = (x + 3)$ units, Find PS.

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