In square □ABCD, join AC. Let O be midpoint of AC and AO⊥BD.
Which one of following is true?
BO and CO are respectively the bisectors of angle B and C of ∆ABC. AO produced meets BC at P. Show that AO/BP = AO/OP , AC/CP = AO/OP ,
AB/AC = BP/PC , AP is the bisector of angle BAC.
BO and CO are respectively the bisectors of ∠B and ∠C of ΔABC. AO produced meets BC at P. Show that [4 MARKS]
(i) ABBP=AOOP (ii) ACCP=AOOP (iii) ABAC=BPPC (iv) AP is the bisector of ∠BAC.