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B
27μC
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C
18μC
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D
54μC
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Solution
The correct option is B27μC We can redraw the above circuit diagram as following Value of current in the circuit, i=VReq i=186+6=1.5A Voltage drop across R2,V2=R2i=6×1.5=9V Charge on capacitor (C2=3μF) is a2=C2V2=3×9=27μC.