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Question

In steady state, charge of 3μF capacitor is:
761261_122bbf6cd70c492292a336815bf83341.jpg

A
36μC
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B
27μC
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C
18μC
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D
54μC
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Solution

The correct option is B 27μC
We can redraw the above circuit diagram as following
Value of current in the circuit, i=VReq
i=186+6=1.5 A
Voltage drop across R2,V2=R2i=6×1.5=9V
Charge on capacitor (C2=3μF) is
a2=C2V2=3×9=27μC.
771075_761261_ans_bd323563ae1f45f9b3ec782a73d574ae.jpg

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