Question

In system $A\left(s\right)\rightleftharpoons 2B\left(g\right)+3C\left(g\right)$ at equilibrium if concentration of ${}^{\prime }{C}^{\prime }$ is doubled then concentration of $B$ at equilibrium is:

• A. double its original concentration
• B. half its original concentration
• C. $2\sqrt{2}$ its original concentration
• D. $\frac{1}{2\sqrt{2}}$ its original concentration

Answer 1

The correct option is D $\frac{1}{2\sqrt{2}}$ its original concentration

$A\left(s\right)\rightleftharpoons 2B\left(g\right)+3\left(g\right)$

$K_C={\left[B\right]}^2{\left[C\right]}^3$ (A won't come in equation because of it's solid nature)

If $C$ is doubled

$K_C={\left[B\right]}^2{\left[C\right]}^3={\left[B^1\right]}^2{\left[C^1\right]}^3$

$={\left[B^1\right]}^2{\left[2C\right]}^3$

$\Rightarrow {\left[B^1\right]}^2=\frac{1}{8}{\left[B\right]}^2$

$B^1=\frac{1}{2\sqrt{2}}\left[B\right]$