Question

In $TeC{l}_4$, the central atom tellurium involves:

• A. $s{p}^3$ hybridisation
• B. $s{p}^{3}d$ hybridisation
• C. $ds{p}^2$ hybridisation
• D. $s{p}^3{d}^2$ hybridisation

Answer 1

The correct option is B $s{p}^{3}d$ hybridisation

Number of hybrid orbitals $=\frac{1}{2}$ (no. of electrons in valence shell of atom + no. of monovalent atoms - charge no cation + charge on the anion

Number of hybride orbitals $=\frac{1}{2}(6+4+0+0)=5$

Hence, $TeC{l}_4$ shows $s{p}^{3}d$ hybridisation.

Therefore, option B is correct.