Question

In th population of a diploid organism exhibiting Hardy - Weinberg equilibrium, the frequency of a recessive gene can be found out by calculating the value of:

• A. $p^2$
• B. q
• C. 2pq
• D. $q^2$

Answer 1

The correct option is D $q^2$

The Hardy - Weinberg equation is based on the Mendelian principle of segregation along with the simple probability to explain the relationship between allelic and genotypic frequencies in a population. According to them, the in a population of diploid organisms obeying the conditions of the equilibrium can be represented the equation p+q=1, where p and q are frequencies of dominant and recessive alleles, its binomial expansion is written as $p^2+2\mathrm{pq}+q^2=1$, where $p^2$ is the genotypic frequency of homozygous dominant, 2pq is the frequency of heterozygous, and $q^2$ is the frequency of homozygous recessive genotypes in a population.