In the A HBr−−−→ B alcKOH−−−−−−→ C Zn/H2O−−−−−→O3CH3CHO+HCHO the compound A is :
A
ethylene
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B
acetic acid
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C
propene
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D
1- butene
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Solution
The correct option is C propene Reaction: CH3CH=CH2HBr−−−→CH3CHBr−CH3alcKOH−−−−−−→CH3CH=CH2Zn/H2O−−−−−→O3CH3CHO+HCHO so compound A is CH3CH=CH2 (Propene).
It on reaction with HBr undergoes hydrohalogenation to form propyl bromide which on reaction with alc. KOH undergoes beta elimination reaction to form propene. This propene finally undergoes ozonolysis followed by hydrolysis to form acetaldehyde and formaldehyde as a product.