Question

In the above diagram,
$\angle B$ : $\angle C$ = 2 : 3.$\angle B$ is ${\left(\frac{206}{5}\right)}^{\circ }$ .

• A. True
• B. False

Answer 1

The correct option is A True

$\angle B:\angle C$= 2: 3

Let, $\angle B=2x$ and $\angle C=3x$

Also, $\angle B+\angle C={103}^{\circ }$ (Exterior angle of a triangle is equal to the sum of opposite interior angles)

$2x+3x={103}^{\circ }$

$x={\frac{103}{5}}^{\circ }$

Hence, $\angle B=2\times {\frac{103}{5}}^{\circ }$

$\angle B={\frac{206}{5}}^{\circ }$