In the above figure, calculate the area of the shaded region.

c^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{(x + c)}^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 x c + c^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is E $2 x c + c^{2}$
The length of the side of the above given bigger square is $(x + c)$ .
The length of the smaller square is $x$ .
The required area is:
Area of bigger square $-$ area of smaller square
$= (x + c)^{2} - x^{2}$
$= x^{2} + 2 c x + c^{2} - x^{2}$
$= c^{2} + 2 c x$ sq units

Suggest Corrections

Similar questions

y = x^{2} - c^{2}

y = c^{2} - x^{2}

C_{1}

C_{2}

C_{1}

C_{1}

C_{2}

y = x^{2}

C_{1}

y = x^{2} / 2

$In a triangle ABC, if ∠ A = 60^{0}, a = 5, b = 4, then c is a root of the equation$

\frac{{(x^{a + b})}^{2} {(x^{b + c})}^{2} {(x^{c + a})}^{2}}{{(x^{a} . x^{b} . x^{c})}^{4}}

In the above compound, $C_{2}$ is rotated clockwise $120^{\circ}$ about $C_{2} - C_{3}$ bond. The resulting conformer is:

Join BYJU'S Learning Program