In the above figure first derivative (f’(x)) of the function y = f(x) at point P will be equal to

sin(ψ)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

cos(ψ)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

tan (ψ)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

None of the above

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
tan (ψ)

We know that the first derivative of a function at any point is equal to the slope of the tangent drawn to the curve at that point. We also know that the slope of a straight line is tan $(θ)$ , if the angle made by the line with the positive side of x -axis is $θ$ .

Suggest Corrections

Similar questions

In the above figure first derivative (f’(x)) of the function y = f(x) at point P will be equal to

The above figure is the graph of a continuous and differentiable function y = f(x). Between point A & B the function has its derivative zero at how many points -

Q. For a real number y, let [y] denote the greatest integer less than or equal to y. Then the function

f (x) = \frac{t a n π [(x - π)]}{1 + [x]^{2}}

Q. For the function y = f(x) the formal definition of derivative is

f^{'} (x) = {lim}_{Δ x \to 0} f (X + Δ X) - f (X) .

Q. The first and second order derivatives of a function f(x) exist at all points in (a,b) with

f^{'} (c) = 0

, where

a < c < b

. Further more, if

f^{'} (x) < 0

at all points on the immediate left of

c

and

f^{'} (x) > 0

for all points on the immediate right of

c

, then at

x = c, f (x)

has a

Join BYJU'S Learning Program

In the above figure first derivative (f’(x)) of the function y = f(x) at point P will be equal to

The correct option is C tan (ψ) We know that the first derivative of a function at any point is equal to the slope of the tangent drawn to the curve at that point. We also know that the slope of a straight line is tan (θ), if the angle made by the line with the positive side of x -axis is θ.