Question

In the above figure, $\frac{1}{2}\left(\angle BCA\right)=\left(\frac{1}{2}\angle BAZ\right)$

• A. True
• B. False

Answer 1

The correct option is A

True

Yes, in the above figure, $\frac{1}{2}\left(\angle BCA\right)=\left(\frac{1}{2}\angle BAZ\right)$ because according to the alternate segment theorem, the angle between a tangent and a chord through the point of contact is equal to an angle made by the chord in the alternate segment.

$\therefore \angle BCA=\angle BAZ$

So, $\frac{1}{2}\left[\angle BCA\right]=\frac{1}{2}\left[\angle BAZ\right]$

Hence, the statement mentioned above is true.