Question

In the above figure, if OA $=$ OB, OD $=$ OC then $\Delta AOD\cong \Delta BOC$ by congruence rule :

• A. $SSS$
• B. $ASA$
• C. $SAS$
• D. $RHS$

Answer 1

The correct option is C $SAS$

In $△AOD$ and $△BOC$

$OA=OB$ -------(given)

$OD=OC$ -------(given)

$\angle AOD=\angle BOC$

$\therefore △AOD\cong △BOC$ by $SAS$ criteria.