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Question

In the above figure O is the center of the circle and AOB = 80, then match the following.

AngleValue1. ACB a. 902. ADBb. 403. ABCc. 804. AOCd. 180


A

a-1, b-2, c-3, d-4

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B

a-2, b-1, c-3, d-4

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C

a-4, b-3, c-2, d-1

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D

a-3, b-2, c-2, d-1

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Solution

The correct option is C

a-4, b-3, c-2, d-1


AOC is a straight line, so AOC should be a straight angle. Therefore AOC= 180.

Diameter is also a chord of the circle. The angle subtended by AC at the center is AOC = 180.

Since the angle subtended by a chord at the center is equal to twice the angle subtended by it at any other point on the circle.

We get AOC = 2 ABC

ABC = 90

Similarly, ADB = 12 AOB

ACB= 12 AOB

From the above, we can see that ADB = ACB = 12 AOB

ADB = ACB = 40


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