In the above figure- what is the length of EF given that - DEF -90- -A- 20 cmB- 10 cmC- 15 cmD- 5 cm

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Proportion in Similar Triangles

In the above ...

Question

In the above figure, what is the length of EF given that $∠ D E F = 90 °$ ?

20 cm

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10 cm

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15 cm

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5 cm

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Solution

The correct option is B
10 cm

The given $△ A B C \sim △ D E F$ by AAA Similarity Criterion

Hence the sides will be proportional , $\Rightarrow \frac{A C}{D F} = \frac{B C}{E F}$

$\Rightarrow \frac{3}{6} = \frac{5}{E F}$

Thus, EF = 10 cm

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Q. In this figure

∠ D E F = 90^{\circ}

seg

E P ⊥ D E

Prove that

\frac{E F}{F P} = \frac{D F}{D E}

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In the above figure, what is the length of EF given that ∠DEF=90° ?

The correct option is B 10 cm The given △ABC∼△DEF by AAA Similarity Criterion Hence the sides will be proportional , ⇒ACDF=BCEF ⇒36=5EF Thus, EF = 10 cm

In the above figure, what is the length of EF given that $∠ D E F = 90 °$ ?

The correct option is B
10 cm

The given $△ A B C \sim △ D E F$ by AAA Similarity Criterion

Hence the sides will be proportional , $\Rightarrow \frac{A C}{D F} = \frac{B C}{E F}$

$\Rightarrow \frac{3}{6} = \frac{5}{E F}$

Thus, EF = 10 cm