Question

In the above question, if the motion of the pulse and rotation of the loop, both are in same direction then the velocity of the pulse with respect to ground will be:

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

Velocity of rope w.r.t. ground will be $V_{RG}=\omega R=\frac{\omega L}{2\pi }$
As obtained in the previous question, the velocity of pulse w.r..t. rope is given by,
$V_{PR}=\frac{\omega L}{2\pi }{V}_{PR}=V_{PG}-V_{RG}=\frac{\omega L}{2\pi }\Rightarrow V_{PG}-\frac{\omega L}{2\pi }=\frac{\omega L}{2\pi }\therefore V_{PG}=\left(\frac{wL}{2\pi }\right)2=\frac{\omega L}{\pi }$