In the above reaction, Hofmann product is major when X is

-I

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-Cl

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-Br

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-F

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Solution

The correct option is D -F
Hofmann product is the least substituted alkene product.
Generally, Hofmann product is the major product when bulky base is used or when the leaving group in E2 is poor.

Among the halogens, $- F$ is the poor leaving group due to its strong bond of $C - F$ . Hence, substate having $- F$ leaving group will give Hofmann product as major.

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