In the above reaction molecular formula of glycerol increases by :

C H_{4} H_{4} O_{2}

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C H_{6} H_{6} O_{6}

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C H_{6} H_{6} O_{2}

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C H_{6} H_{6} O_{3}

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Solution

The correct option is D $C H_{6} H_{6} O_{3}$

(Refer to Image)
$O$
$A C \Rightarrow | | C - C H_{3} = C_{2} H_{3} O$ . So on change with hydrogen the change is $C_{2} H_{2} O$ . There are three $O H$ groups so change is $C_{6} H_{6} O_{3}$

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C_{2} H_{5} O H C u / 300^{o} C - ----- \to X

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i) 2 H_{2} O_{2} \to Pt 2 H_{2} O + O_{2} ii) 2 H_{2} O_{2} - --- \to Glycerol 2 H_{2} O + O_{2}

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A + B ⇌ C

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