In the above reaction rate is fastest, when (X) is:

-OH

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N H_{2}

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- O | | S | | O - O C H_{3}

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- O - O | | S | | O - C H_{3}

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Solution

The correct option is D $- O - O | | S | | O - C H_{3}$
$- O H$ and $- N H_{2}$ are bad leaving group while $- O | | S | | O - O C H_{3}$ and $- O - O | | S | | O - C H_{3}$ are good leaving group. In a good leaving group conjugate base is least basic or most stable.

$- O | | S | | O - ¨ O C H_{2}^{-}$ Carbanion less stable due to $+ R$ effect of $- ¨ O -$ group

$- O | | S | | O - C H_{2}^{-}$ Carbanion more stable due to $- R$ effect of $- O | | S | | O - C H_{2}^{-}$ group.

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Similar questions

Q. Arrange the following compounds in decreasing order of reactivity towards nucleophilic addition reaction.

C H_{3} - O | | C I - C H_{3}

C H_{3} - O | | C I I - C l

C H_{3} - O | | C I I I - N H_{2}

C H_{3} - O | | C I V - O H

C H_{3} - O | | C - O V - O | | C - C H_{3}

(x)

C H_{3} - O | | S | | - O O - H

(y)

C H_{3} - O | | C - O - H

(z)

C H_{3} - O H

Set the following in increasing order of their

p K_{a}

values.

Which of the following is not correct?

$O r d e r o f b a s i c i t y O r d e r o f n u c l e o p h i l i c i t y (a) F^{-} > C l^{-} > B r^{-} B r_{-} > C l^{-} > F^{-} (b) H - O - O^{-} > O H^{-} H - O - O^{-} > O H^{-} (c) C H_{3} > N H_{2}^{-} > O H - C H_{3} > N H_{2}^{-} > O H^{-} (d) H_{2} O > H_{2} S H_{2} O < H_{2} S$

C H_{3} - C \equiv C - C H_{3} (i) x - ------ \to (i i) Z n / H_{2} O

C H_{3} - C | | O - C | | O - C H_{3}

In the above reaction

x

is:

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