Question

In the above reaction X is:
$C{H}_3-C\equiv C-C{H}_3\underset{\left(ii\right)H_{2}O/Zn}{\overset{\left(i\right)X}{\to }}C{H}_3-\underset{O}{\underset{||}{C}}-\underset{O}{\underset{||}{C}}-C{H}_3;X$

• A. $HN{O}_3$
• B. $O_2$
• C. $O_3$
• D. $KMn{O}_4$

Answer 1

The correct option is C $O_3$

$C{H}_3-C\equiv C-C{H}_3\underset{\left(ii\right)Zn/H_{2}O}{\overset{\left(i\right)O_3}{\to }}C{H}_3-\underset{O}{\underset{||}{C}}-\underset{O}{\underset{||}{C}}-C{H}_3$

In above reaction, X is $O_3$. In this reaction is Ozonolysis take place.

Ozonolysis is an organic reaction where the unsaturated bonds of alkenes, alkynes or azo compounds are cleaved with ozone molecule.

The reagent used in this reaction is ozone.