Question

In the above setup of voltameter, the electrolysis of NaCl is carried out. What ions will be on A and B?

• A. A: $C{l}^{-}$ ions and B: $N{a}^{+}$ ions
• B. A: $N{a}^{+}$ ions and B: $C{l}^{-}$ ions
• C. A: $H^{+}$ ions and B: $C{l}^{-}$ ions
• D. A: $C{l}^{-}$ ions and B: $H^{+}$ ions

Answer 1

The correct option is A

A: $C{l}^{-}$ ions and B: $N{a}^{+}$ ions

In the electrolysis of NaCl the anode will have $C{l}^{-}$ ions while the cathode will have $N{a}^{+}$ ions. So:

A: $C{l}^{-}$ ions

B: $N{a}^{+}$ ions