Question

In the above sided figure,if $QT\perp PR.,\angle TQR={40}^o$ and $\angle SPR={30}^o$,find $x$ and $y$

Answer 1

In $\Delta QTS$, the nagles are: ${40}^o,{90}^o,x$

Using sum of angles of triangle property:

${40}^o+{90}^o+x={180}^o⟹={50}^o$
$y$ is and exterior angle of $\Delta PSR$, using the property of exterior angle:
$y={30}^o+x={80}^o$
$x={50}^o,y={80}^o$