Question

In the AC circuit, the current is expressed as $I=100\sin 200\pi t$. In this circuit current rises from zero to peak value in time

• A. $\frac{1}{400}s$
• B. $\frac{1}{300}s$
• C. $\frac{1}{100}s$
• D. $\frac{1}{200}s$

Answer 1

The correct option is A $\frac{1}{400}s$

At $t=0$ we have $I=0$

putting $I=100$ i.e., peak value in the expression we get $sin200\pi t=1$ that is angle equal to $\pi /2$ or $200\pi t=\pi /2$

thus we get $t=1/400$ $second$