Question

In the $AC$ network shown in figure, the rms current flowing through the inductor and capacitor are $0.6A$ and $0.8A$ respectively. Then the current coming out of the source is

• A. $1.0A$
• B. $1.4A$
• C. $0.2A$
• D. None of the above

Answer 1

The correct option is C $0.2A$

$I_C$ is ${90}^o$ ahead of the applied voltage and $I_L$ lags behind
the applied voltage by ${90}^o$. So, there is a phase difference of
${180}^o$ between $I_L$ and $I_C$.
$\therefore I=I_C-I_L=0.2A$