Question

In the acid catalysed hydrolysis of ester the volume of base required at various instant are as follows.

Time	0	10 sec	$t_{\infty }$
$V_{NaOH}$	24 mL	32 mL	40 mL

If hydrolysis follows first order kinetics then find its rate constant (approx).

• A. $7\times {10}^{-2}{s}^{-1}$
• B. $14\times {10}^{-2}{s}^{-1}$
• C. $7\times {10}^{-2}s$
• D. $14\times {10}^{-2}s$

Answer 1

The correct option is A $7\times {10}^{-2}{s}^{-1}$

$a_0=40-24=16$
$x=32-24=8$
$In\left(\frac{a_0}{a_0-x}\right)=k.t$
$k=\frac{ln\left(\frac{16}{8}\right)}{10}=\frac{ln\left(2\right)}{10}=7\times {10}^{-2}{s}^{-1}$