In the adjacent diagram, if $n (U) - 125, y$ is two times of $x$ and $z$ is $10$ more than $x$ . then find the value of $x, y$ and $z$

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Solution

$\begin{matrix} \Rightarrow n (0) = 125 \Rightarrow y = 2 x (g i v e n) \to (i) \Rightarrow z = x + 10 (g i v e n) \to (i i) T h e n, A / q t o d i a g r a m \Rightarrow x + 4 + 3 + 6 + y + 3 + 4 + 17 + 6 + 3 + 17 + z = 125 f r o m e q u a t i o n (i), (i i) a n d (i i i) \Rightarrow x + y + z = 125 - 63 \Rightarrow x + 2 x + x + 10 = 62 \Rightarrow 4 x = 52 ⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} x = 13 ∴ y = 2 x = 2 \times 13 = 26 ∴ z = x + 10 = 23 \end{matrix} ⎫ ⎪ ⎬ ⎪ ⎭ A n s . \end{matrix}$

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