Question

In the adjacent figure, AOB is a straight line and $\angle AOD=120,\angle BOC=110$, then find $\angle COD$?

Answer 1

Let $\angle AOC={120}^{\circ }-x,\angle COD=x,\angle BOD={110}^{\circ }-x$ and the total angle will be ${180}^{\circ }$.

${120}^{\circ }-x+x+{110}^{\circ }-x={180}^{\circ }⟹x={50}^{\circ }$