Question

in the adjacent figure , parallelogram $ABCD$ , Show that $ABC\cong CDA$

Answer 1

$\begin{array}{c}In\Delta ABC\&\Delta CDA\\ AB=CD\\ BC=DA\end{array}$

(opposite side of parallelogram are equal)

$\angle ABC=\angle CDA$ Oppsite angle in parallelogram are equal

$\therefore \Delta ABC\cong \Delta CDA\left(SAScongurencerule\right)$