Question

In the adjoining circuit, initially the switch $S$ is open. The switch $S$ is closed at $t=0$. The difference between the maximum and minimum current that can flow in the circuit is

• A. $2A$
• B. $3A$
• C. $1A$
• D. nothing can be concluded

Answer 1

The correct option is C $1A$

At $t=0$ the inductor behaves like infinite resistance,

$i_{min}=\frac{10}{10}=1A$

At $t=\infty$, the inductor behaves like a short circuited wire

$i_{max}=\frac{10}{5}=2A$

Therefore, $i_{max}-i_{min}=2-1=1A$.