In the adjoining circuit of logic gate, the output Y becomes zero if the inputs are
A
A=1,B=1,C=0
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B
A=0,B=0,C=0
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C
A=0,B=1,C=1
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D
A=1,B=0,C=0
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Solution
The correct option is AA=1,B=1,C=0 The output Y=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(A⋅B)⋅C=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(A⋅B)+¯¯¯¯¯¯¯¯¯C =¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(A⋅B)+C So, Y=0 if A=1,B=1 and C=0.