In the adjoining fig- ABCD is a quadrilateral such that - O - - C - 100- the bisector of - A and - B meet at - P- Determine - APB-

In quadrilateral ABCD, AP and BP are the bisectors of A and B then APB= 1 2 C+D.(Angle bisector theorem) ∴∠ APB=100+60 ÷ 2=80 ...

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Byju's Answer

Standard IX

Mathematics

Every Point on the Bisector of an Angle Is Equidistant from the Sides of the Angle.

In the adjoin...

Question

In the adjoining fig. $A B C D$ is a quadrilateral such that $∠ O + ∠ C = 100^{\circ}$ . the bisector of $∠ A$ and $∠ B$ meet at $∠ P$ . Determine $∠ A P B$ .

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Solution

In quadrilateral ABCD, AP and BP are the bisectors of A and B then APB= $\frac{1}{2}$ C+D.(Angle bisector theorem)
$∴ ∠ A P B = 100 + 60 \div 2 = 80$

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In the adjoining fig. ABCD is a quadrilateral such that ∠O+∠C=100∘. the bisector of ∠A and ∠B meet at ∠P. Determine ∠APB.

In quadrilateral ABCD, AP and BP are the bisectors of A and B then APB=12 C+D.(Angle bisector theorem)∴∠APB=100+60÷2=80

In the adjoining fig. $A B C D$ is a quadrilateral such that $∠ O + ∠ C = 100^{\circ}$ . the bisector of $∠ A$ and $∠ B$ meet at $∠ P$ . Determine $∠ A P B$ .

In quadrilateral ABCD, AP and BP are the bisectors of A and B then APB= $\frac{1}{2}$ C+D.(Angle bisector theorem)
$∴ ∠ A P B = 100 + 60 \div 2 = 80$