Question

In the adjoining fig. along which axis the M.I. of the triangular lamina will be maximum- (given that $AB<BC<AC)$

• A. AB
• B. BC
• C. CA
• D. For all axis

Answer 1

The correct option is A AB

$\begin{array}{c}\text{For a Triangular Lamina the moment}\\ \text{of Inertia along a side is given by}\\ I=\frac{m{h}^2}{6}\text{whose}h\text{is the perpendicular}\\ \text{drawn from opposite vertex to the side}\end{array}$

$\begin{array}{c}AB\angle BP\angle BC\\ \text{Therefore moment of inertia about}AB\text{is}\\ \text{maximum}\\ \text{Hence option}A\text{is correct}\end{array}$