In the adjoining figure, a star is shown, What is the sum of the angles A, B, C, D and E?

120^{\circ}

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180^{\circ}

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240^{\circ}

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C a n^{'} t b e d e t e r m i n e d

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Solution

The correct option is B $180^{\circ}$
$(∠ B P Q + ∠ B Q P) + (∠ E Q R + ∠ E R Q) + (∠ C R S + ∠ C S R) + (∠ T S A + ∠ A T S)$
$+ (∠ D T P + ∠ D P T) = 2 \times 360$
$∠ A + ∠ D + ∠ B + ∠ E + ∠ C = 5 \times 180^{\circ} - 2 \times 360^{\circ} = 180^{\circ}$

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