In the adjoining figure, AB = 10 cm, BC =15 cm AD : DC = 2 : 3, then \(\angle\)ABC is equal to -
40∘
Clearly, ADDC = 23 and ABBC = 1015 = 23
So, ADDC = ABBC
Thus, BD divides AC in the ratio of the other two sides.
By Converse of Angular Bisector theorem,
BD is the bisector of ∠B
∴ ∠ABC = 2 ( ∠CBD)
Now, ∠CBD = 180∘ - (130∘ + 30∘) .... (Angle Sum Property)
= 20∘
But , ∠ABC = 2 ( ∠CBD)
= 2 x 20
= 40∘