In the adjoining figure, AB = AC and AP $\bot $ BC.

Which of the following option is correct?

AB = AP

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AB < AP

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AB > AP

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AB ≤ AP

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Solution

The correct option is C
AB > AP

Since perpendicular distance is smallest, we have AB > AP.

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Similar questions

In the adjoining figure, when $A B = A C$ and $A P ⊥ B C,$ then $A B > A P$

In the adjoining figure, AB = AC and AP $⊥$ BC.

Which of the following option is correct?

In the figure, AB = AC and AP $⊥$ BC. Then

A B = A C

A P ⊥ B C

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