In the adjoining figure, AB=AC and AP⊥BC
Which of the following options is correct?
AB = AP
AB < AP
AB > AP
AB ≤ AP
Since AP is perpendicular to side BC.
In △ABP,
∠APB=90∘
So △ABP is a right angled triangle where AB is the hypotenuse.
∴AB>AP
In the figure, AB = AC and AP ⊥ BC. Then
In the adjoining figure, when AB=AC and AP⊥BC, then AB>AP
In the figure, 2 AD = AB, P is the mid point of AB, Q is mid point of DR and PR∥BS. Then, DSRS=
In the adjoining figure, AB = AC and AP ⊥ BC.
Which of the following option is correct?