Question

In the adjoining figure $AB=AD$ and $CB=CD$ Prove that $△ABC\cong △ADC$

Answer 1

Given:- $AB=ADCB=CD$

To prove;- $△ABC\cong △ADC$

Proof:-

In $△ABC$ and $△ADC$,

$AB=AD\left(\text{Given}\right)$

$CB=CD\left(\text{Given}\right)$

$AC=AC\left(\text{Common}\right)$

$\therefore △ABC\cong △ADC\left(\text{By SSS congruence property}\right)$