Question

In the adjoining figure, AB || CD and EF is transversal. the value of $x-y$ is

• A. ${75}^0$
• B. ${40}^0$
• C. ${35}^0$
• D. none

Answer 1

The correct option is B ${40}^0$

$\angle MFD+y=\angle FEP+x$

${180}^0-{60}^0+y={180}^0-({60}^0+{40}^0)+x$

$x-y={40}^0$