Question

In the adjoining figure, ABCD is a rectangle and DF = CF also, AE = 3BE. What is the value of $\angle EOF,if\angle DFO={28}^{\circ }and\angle AEO={42}^{\circ }?$

• A. ${14}^{\circ }$
• B. ${42}^{\circ }$
• C. ${70}^{\circ }$
• D. ${90}^{\circ }$

Answer 1

The correct option is C ${70}^{\circ }$

$\angle DFO=\angle FOMand\angle AEO=\angle EOM\left(sinceCD||AB\right)$

$\therefore \angle FOE=({28}^{\circ }+{42}^{\circ })={70}^{\circ }$