In the adjoining figure ABCD, P and R are the mid-points of the sides AB and CD. ABCD is a parallelogram. What is the ratio of the shaded to the unshaded region?

\frac{1}{2}

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\frac{1}{3}

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\frac{1}{4}

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Solution

The correct option is B $\frac{1}{3}$
There are total 16 similar triangles each with equal area.

Here, 4 out of 16 triangles are taken. So the number of shaded triangles = 4 and number of unshaded triangles = 12
$∴$ Required $= \frac{1}{3}$

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In the adjoining figure ABCD, P and R are the mid-points of the sides AB and CD. ABCD is a parallelogram. What is the ratio of the shaded to the unshaded region?

The correct option is B 13There are total 16 similar triangles each with equal area. Here, 4 out of 16 triangles are taken. So the number of shaded triangles = 4 and number of unshaded triangles = 12 ∴ Required =13

The correct option is B $\frac{1}{3}$
There are total 16 similar triangles each with equal area.

Here, 4 out of 16 triangles are taken. So the number of shaded triangles = 4 and number of unshaded triangles = 12
$∴$ Required $= \frac{1}{3}$