In the adjoining figure, $A C =$

25

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25 \sqrt{3}

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\frac{25}{\sqrt{3}}

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25 \sqrt{2}

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Solution

The correct option is B $25 \sqrt{3}$ m
We have,
$A B = 25 m$
$A C = ?$

In $△ A B C,$
$tan 60^{0} = \frac{A C}{A B}$

$\sqrt{3} = \frac{A C}{25}$

$A C = 25 \sqrt{3} m$

Hence, this is the answer.

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Similar questions

Find the area of a rectangular plot which is $4 \frac{2}{5} m$ long and $6 \frac{3}{5} m$ broad.

v (t) = t^{2} - 5 t m/s

10 sec

m^{2} - 25

(m + 25) (m - 25)

\frac{3}{5 - \sqrt{3}} + \frac{2}{5 + \sqrt{3}}

\frac{25 + \sqrt{m}}{22}

m

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