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Question

In the adjoining figure, angle subtended by the arc AB at the center of smaller and bigger cirles are 60 and 40 respectively, then CAD is


A
80
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B
130
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C
120
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D
100
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Solution

The correct option is B 130

Arc AB makes 60 at the center of the smaller circle. So, ADB will be half of 60
i.e. ADB=602
=30
ADB=ADC=30

Arc AB makes 40 at the center of the bigger circle. So, ACB will be half of 40
i.e. ACB=402
=20
ADB=ACD=20
Now,
ACD+CDA+DAC=180
20+30+DAC=180
DAC=18050
DAC=130
Thus, DAC or CAD is 130.

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