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Question

In the adjoining figure, B=90°, BAC=θ°, BC=CD=4 cm and AD=10 cm. Find i sinθ and ii cosθ.

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Solution


In ABD,

Using Pythagoras theorem, we get

AB=AD2-BD2=102-82=100-64=36=6 cm

Again,

In ABC,

Using Pythagoras therem, we get

AC=AB2+BC2=62+42=36+16=52=213 cm

Now,

i sinθ=BCAC=4213=213=21313

ii cosθ=ABAC=6213=313=31313

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