Question

In the adjoining figure, $BA\perp AC,DE\perp DF$ such that $BA=DE$ and $BF=EC$. Show that $\Delta ABC\cong \Delta DEF$

Answer 1

In $△ABC,△DEF$

$BA=ED$

$BF=EC$

$⟹BF+FC=FC+EC$

$BC=EF$

$\angle BAC=\angle EDF={90}^{\circ }$

By $S.A.S$ congruency

$△ABC\cong △DEF$