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Question

In the adjoining figure, BAAC,DEDF such that BA=DE and BF=EC. Show that ΔABCΔDEF
1130843_6753127a455445a6b6cd77a2e5bd2257.png

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Solution

In ABC,DEF
BA=ED
BF=EC
BF+FC=FC+EC
BC=EF
BAC=EDF=90
By S.A.S congruency
ABCDEF

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