Question

In the adjoining figure, BD and CD are angle bisectors. Then, which of the following is true ?

• A. $\angle D=\frac{1}{2}\angle A$
• B. $\angle x+\angle y=\angle A+\angle D$
• C. $\angle D=\frac{\angle x+\angle y}{2}$
• D. All of above

Answer 1

The correct option is A $\angle D=\frac{1}{2}\angle A$

From figure, $2y=A+2x$ and $y=D+x$
$2D+2x=A+2x$
$\therefore \angle D=\frac{1}{2}\angle A$