wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the adjoining figure block A is of mass m and block B is of mass 2m. The spring has force constant k. All the surfaces are smooth and the system is released from the rest with spring unstretched. Then:
117452.png

A
The maximum extension of the spring is 4mgk
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Tension in the thread for extension of 2mgk in spring is mg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Net acceleration of block B when the extension in the spring is maximum, is 23g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct options are
A The maximum extension of the spring is 4mgk
C Net acceleration of block B when the extension in the spring is maximum, is 23g
(a) Decrease in potential energy of B = increase in spring potential energy
2mgxm=12kx2m
xm=4mgk

(b) Ei=Ef
0=12(m+2m)v2+12×k×(2mgk2)(2mg)(2mgk)
v=2gm3k

(c) a=kxm2mg3m (upwards)
=k(4mgk)2mg3m=2g3

(d) T2mg=ma.....(i)
2mgT=2ma.....(ii)
Solving these two equations, we get
a=0 and T=2mg

133745_117452_ans.jpg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Energy in SHM
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon