In the adjoining figure, DE || AB,

AD = 7 cm, CD = 5 cm and BC = 18 cm

Find (i) BE (ii) CE

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Solution

The given figure is:

It is given that DE || AB, AD = 7 cm, CD = 5 cm and BC = 18 cm.

We need to find (i) BE and (ii) CE

In ΔABC, DE || AB,

Applying Basic Proportionality Theorem, we get:

Now, CE = BC –BE = 18 –7.5 = 10.5 cm

Hence,

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Similar questions

In the following figure, $D E ∥ A B$ . If $A D = 7 c m, C D = 5 c m$ and $B C = 18 c m$ , find $C E$ .

∠ B = 90 °, ∠ BAC = θ °, BC = CD = 4 cm and AD = 10 cm . Find (i) \sin θ and (ii) \cos θ .

Construct a quadrliateral ABCD; if:

(i) AB = 4.3 cm, BC = 5.4, CD = 5 cm, DA = 4.8 cm and $∠$ ABC = $75^{\circ}$ .

(ii) AB = 6 cm, CD = 4.5 cm, BC = AD = 5 cm and $∠ BCD = 60^{\circ}$

(iii) AB = 8 cm, BC = 5.4 cm, AD = 6 cm, $∠ A = 60^{\circ}$ and $∠ B = 75^{\circ}$ .

(iv) AB = 5 cm, BC = 6.5 cm, CD = 4.8 cm, $∠ B = 75^{\circ}$ and $∠ C = 120^{\circ}$

(v) AB = 6 cm = AC, BC = 4 cm, CD = 5 cm and AD = 4.5 cm.

(vi) AB = AD = 5 cm, BD = 7 cm and BC = DC = 5.5 cm

△ A D C \sim △ B E C

C A \times C E = C B \times C D

△ A B C \sim △ D E C

C D \times A B = C A \times D E

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