wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the adjoining figure, DE is a chord parallel to diameter AC of the circle with centre O. If ∠CBD = 60°, calculate ∠CDE.

Open in App
Solution


Angles in the same segment of a circle are equal.
i.e., CAD = CBD = 60°
We know that an angle in a semicircle is a right angle.
i.e., ADC = 90°
In ΔADC, we have:
ACD + ADC + CAD = 180° (Angle sum property of a triangle)
ACD + 90° + 60° = 180°
ACD = 180° – (90° + 60°) = (180° – 150°) = 30°
CDE = ACD = 30° (Alternate angles as AC parallel to DE)
Hence, CDE = 30°

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
SSS Congruency
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon